Nobody Special: I know that I know how to do this problem, but for some reason it's not coming out right. Could someone show me how to do this?
I have the answer, I just forgot how to get to it.
lg2 (4 - 3x) = 5
Many thanks! ^_^
Hi Special It is really good to see you here again.
I think that you want
log
2(4-3x) = 5 [ that is, log base 2 of (4-3x) = 5 ]
There is a couple of different ways to think about this
If log
ba = x
then a=b
x Remember: A log is a power. That is a really important thing to keep in your mind.
If you rearrange your equation like this it should become easy.
Method 2.
This uses log identities
If
y=log
3x
then you can solve it like this (I am have trouble finding the right words so I will just show you0
3
y= 3
log3x the 3 and the log base 3 cancel each other out so you are left with
3
y= x
The two methods are really the same. Just different ways to think about it. You should be comfortable with both.
I haven't answered your question exactly but have I given you enough information?
If you get stuck please post again.
and again, it is really good that you are back.