+55 How much heat energy is associated with the reaction of 135 g of aluminum metal with excess hydrochloric acid?
The chemical equation is 2Al + 6HCl = 2AlCl3 + 3H2
\(\Delta {H}_{rxn} = -1052kJ/{mol}_{rxn}\)
My answer is 5260 kJ because there is 5 moles of aluminum reacting, (5 · 1052 = 5260) but I do not believe my answer is correct. I feel like I'm missing something. Please help?
+37146 Aluminum molar weight 26.981 gm /mole
135 gm / 26.981 gm/mole =5.00 moles
It takes TWO moles of aluminum per reaction ( 2 Al in the equation)
5 moles/ 2moles/rxn x -1052 kj/rxn = - 2631 kj
+37146 Aluminum molar weight 26.981 gm /mole
135 gm / 26.981 gm/mole =5.00 moles
It takes TWO moles of aluminum per reaction ( 2 Al in the equation)
5 moles/ 2moles/rxn x -1052 kj/rxn = - 2631 kj
