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How much heat energy is associated with the reaction of 135 g of aluminum metal with excess hydrochloric acid?

 

The chemical equation is 2Al + 6HCl = 2AlCl3 + 3H2 

 \(\Delta {H}_{rxn} = -1052kJ/{mol}_{rxn}\)

 

My answer is 5260 kJ because there is 5 moles of aluminum reacting, (5 · 1052 = 5260) but I do not believe my answer is correct. I feel like I'm missing something. Please help?

 Dec 31, 2018

Best Answer 

 #1
avatar+18293 
+2

Aluminum molar weight  26.981 gm /mole

135 gm  / 26.981 gm/mole =5.00 moles

 

It takes TWO moles of aluminum per reaction   ( 2 Al  in the equation)

 

5 moles/ 2moles/rxn  x -1052 kj/rxn =  - 2631  kj

 Dec 31, 2018
 #1
avatar+18293 
+2
Best Answer

Aluminum molar weight  26.981 gm /mole

135 gm  / 26.981 gm/mole =5.00 moles

 

It takes TWO moles of aluminum per reaction   ( 2 Al  in the equation)

 

5 moles/ 2moles/rxn  x -1052 kj/rxn =  - 2631  kj

ElectricPavlov Dec 31, 2018

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