Given: ∆ABC, D∈ AC, AD: DC = 2:1, E∈ AB, EB: AE = 1:3, F∈ BC, EF ∥ AC, O is the point of the intersection BD and EF. Area of ∆ABC = 216 square units. Find the area of ∆BOE.
The area of triangle BOE is 2*sqrt(3).
