In step 2 it says the slope of \(\overline{AC}\) is \(-{1 \over 2}\), meaning the slope of the altitude is the negative reciprocal, which is 2 not -2.
The line would cross through the point \((2, 1)\), so the equation of this line would be \(y = 2x - 3\).
So, we have to solve this system: \(y = 3\)
\(y = 2x - 3\)