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1. For how many n=2,3,4,...,99,100 is the base-n number 235236_n a multiple of 7?

Guest Feb 1, 2019

edited by
Guest
Feb 1, 2019

#2**+1 **

**If I understand your question: This is the "closed form" of each term: a_n = 1/2 (6 n + (-1)^(n + 1) + 13). And the number 235236(n) is a multiple of 7 in the following bases: n = 10, 12, 16, 18, 22, 24, 28, 30, 34, 36, 40, 42, 46, 48, 52, 54, 58, 60, 64, 66, 70, 72, 76, 78, 82, 84, 88, 90, 94, 96, 100.**

Guest Feb 1, 2019

#1**+1 **

Write it properly and you might have a better chance of a timely answer.

Just edit it and take the $ signs away.

Melody Feb 1, 2019

#2**+1 **

Best Answer

**If I understand your question: This is the "closed form" of each term: a_n = 1/2 (6 n + (-1)^(n + 1) + 13). And the number 235236(n) is a multiple of 7 in the following bases: n = 10, 12, 16, 18, 22, 24, 28, 30, 34, 36, 40, 42, 46, 48, 52, 54, 58, 60, 64, 66, 70, 72, 76, 78, 82, 84, 88, 90, 94, 96, 100.**

Guest Feb 1, 2019