4x-3y = 10
4x+1y=18 Let's just subtract these equations from each other.....this results in the folllowing....
[4x - 3y = 10] 4x - 3y = 10
-[4x + 1y = 18] -4x - 1y = -18
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- 4y = - 8
And dividing both sides by -4, we have that y = 2
And substituting this back into either of the original equations, we can find x...so.....
4x + 1(2) = 18
4x + 2 = 18 subtract 2 from each side
4x = 16 divide by 4 on each side
x = 4
So the solution is : x= 4 and y = 2
4x-3y = 10
4x+1y=18 Let's just subtract these equations from each other.....this results in the folllowing....
[4x - 3y = 10] 4x - 3y = 10
-[4x + 1y = 18] -4x - 1y = -18
----------------
- 4y = - 8
And dividing both sides by -4, we have that y = 2
And substituting this back into either of the original equations, we can find x...so.....
4x + 1(2) = 18
4x + 2 = 18 subtract 2 from each side
4x = 16 divide by 4 on each side
x = 4
So the solution is : x= 4 and y = 2