Expand $3p^5q^3\left( 2pq + \frac{5}{(pq)^2} \right)$
We can write
3p^5q^3 ( 2pq + 5 / (p^2q^2 )
Distributing we have that
3p^5q^3 ( 2pq) + 3p^5q^3 * 5
______
p^2q^2
6p^6q^4 + 15p^5q^3
_________
6p^6q^4 + 15p^2q
Wait, wouldn't that be 6p^6q^4 + 15p^3q or have I miscalculated?
