1. In this problem, all angles are measured in degrees.
Find the smallest angle x such that \(x <90\) and \( 6\tan^2(5x-3) = 2 .\)
\(6tan^2(5x-3)=2\\ tan(5x-3)=\frac{1}{\sqrt3}\\ \quad \text { you should recognise that } \quad tan \frac{\pi}{6} =\frac{1}{\sqrt3}\\ 5x-3=\frac{\pi}{6}\\ \)
And you can finish it.
