need help on #2 #7 and #8 please

2)  6^{5n + 6}  =  1296   --->   6^{5n + 6}  =  6⁴   --->   5n + 6  =  4   --->   5n  =  -2   --->   n  =  -2/5

7)  log₂9 + log₂a  =   log₂13   --->   log₂9a  =  log₂13   --->   9a  =  13   --->   a  =  9/13

8)  log₅(x + 2) - log₅(11)  =  log₅(121)   --->   log₅( (x + 2)/11 )  =  log₅(121)   --->   (x + 2)/11  =  121

              --->   x + 20  =  1331   --->   x  =  1331/20

2.  6^{5n + 6} = 1296    notice that 1296 = 6⁴     so.......we have

6^{5n + 6  =}  6⁴      and equating exponents, we have

5n + 6 =   4        subtract 6 from both sides

5n =   -2            divide both sides by 5

n = -2/5

7. log₂ 9  + log₂ a  = log₂ 13     and we can write

log₂ (9 * a)  = log₂ (13)      and since the logs are the same we have

9a = 13       divide both sides by 9

a = 13/9

8. log₅ (x + 2)  - log ₅ 11  = log₅ 121     and we can write

log ₅ [ (x + 2 ) / 11 ]  =  log ₅ 121      and again, since the logs are the same  we can solve

(x + 2) / 11  = 121     multiply both sides by 11

x + 2   = 1331     subtract 2 from both sides

x  =   1329

no no no, cphill, all they want to know is the fricken answer to the question, not how you got it. you just give them the answer. poor misguided cphill. just give them the fricken answer.....

ahh, i love my job. i get paied $5,000 a week for being awesome!!!

These comments really are not funny TitaniumRome.  The first one is quite rude.