What is the equation of the line that passes through the point(-1, 5) and is parallel to the line y = -3x + 5?
Because the required line is parallel to y= - 3x + 5, the slope of the required line will also be -3. We are just unsure about the constant added.
Now it becomes y = -3x + C
To solve for C, we substitute the x-coordinate of the point into x and y coordinate of the point into y.
5 = (-3)(-1) + C
5 = 3 + C
C = 2
Therefore the slope-intercept equation of the required line is y = -3x + 2