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For some reason my mind has drawn a blank on these kind of problems today.

 

solve for x over the complex numbers.smiley

 

x^2+4x+13=0

 

x=__________ or x=______________

 

Thanks!

Guest Oct 22, 2018
 #1
avatar+9677 
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Solve for x over the complex numbers.

laugh

Omi67  Oct 22, 2018
 #2
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Solve for x:
x^2 + 4 x + 13 = 0

Subtract 13 from both sides:
x^2 + 4 x = -13

Add 4 to both sides:
x^2 + 4 x + 4 = -9

Write the left hand side as a square:
(x + 2)^2 = -9

Take the square root of both sides:
x + 2 = 3 i or x + 2 = -3 i

Subtract 2 from both sides:
x = -2 + 3 i or x + 2 = -3 i

Subtract 2 from both sides:

x = -2 + 3i    or    x = -2 - 3i

Guest Oct 22, 2018

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