In a standard normal distribution, above which Z score do approximately 59% of the Data lie?
1.74
0.23
-0.23
-1.74
If 59% of the data lie above, then we must be at the (100 -59) = 41 percentile
The z score associated with this will be negative .....using a table of z scores.....the z score associated with .41 is ≈ -0.23
+10 
