Calculate how much 10% acid solution and how much pure acid must be mixed to end up with exactly 12 liters of 30% acid solution.
+37153 12 liters final
x = 10%
12-x = 100% solution
.1 x + 1 (12-x) == .3 (12)
.1x + 12 - x = 3.6
.9x =8.4
x = 9 1/3 liters of 10%
+169 So we have 12 liters in the end.
First, we can set acid percentage to 10%
a=.1
And we also have 12-a as the full solution at 100%
Soo..
.1a+12-x=.3(12)
solve the rest
:D
