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Norachai traveled to the recycling plant and back. The trip back took 5 hours. He averaged 9mph faster on the trip there than on the return trip. What was norachai average speed on the outbound trip?

 Feb 6, 2020
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Note: This question was seen before and you missed some crucial info in it, which I have amended.


Norachai traveled to the recycling plant and back. The trip to the plant took 4 hours and the trip back took 5 hours. He averaged 9mph faster on the trip there than on the return trip. What was norachai average speed on the outbound trip?


Let his return trip speed = S
5S = 4(S + 9)
5S =4S + 36
S = 36 mph - his speed on his return
36 + 9 =45 mph - his speed to the plant
5  x  36 =180 miles - distance to the plant
2 *180 / [5+4] =40 mph - his average speed to the plant and back. 

 Feb 6, 2020

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