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Hi. Here is the problem I have on my homework that I need help on.

 

In Super Smash Bros, Lucario is able to get stronger as he hits. His attack strength is 0.7 at 0 damage, but 2.5 strength at 190 damage. The highest he can go is a strength of 3, how much damage would be needed to get to that number (round up if the result becomes a decimal)?

 

It was hard to understand the problem myself, So I tried to make it a little more simple. Let me know if a part of the question does not make sense.

Also, Sorry if my english is bad, english isn't really my best area.

 Oct 1, 2015

Best Answer 

 #1
avatar+130518 
+10

We can set this up as an exponential equation in this form :

 

y = abx   ......where y is  the attack strength, a is .7 , b is to be determined and x is the damage

 

And we're given :

 

2.5 = .7b190    divide both sides by .7

 

2.5/.7 = b190    take the log of both sides

 

log(2.5/.7) = log b190   and we can write this as

 

log(2.5/.7)  = 190 logb   divide both sides by 190

 

log(2.5/.7)/ 190  = log b

 

And this says that  b = 10^[log(2.5/.7)/190]  = about 1.0067

 

And we can solve this :

 

3 = .7(1.0067)x    where x is the damage we're looking for.......divide both sides by .7

 

3/.7  = 1.0067x        take the log of both sides

 

log(3/.7)  = log 1.0067x    and we can write

 

log (3/ .7)  = x log 1.0067      divide both sides by log1.0067

 

log (3 / .7)  / log( 1.0067) =  x  =  about  217.93  = 218  [rounded]

 

 

cool cool cool

 Oct 1, 2015
 #1
avatar+130518 
+10
Best Answer

We can set this up as an exponential equation in this form :

 

y = abx   ......where y is  the attack strength, a is .7 , b is to be determined and x is the damage

 

And we're given :

 

2.5 = .7b190    divide both sides by .7

 

2.5/.7 = b190    take the log of both sides

 

log(2.5/.7) = log b190   and we can write this as

 

log(2.5/.7)  = 190 logb   divide both sides by 190

 

log(2.5/.7)/ 190  = log b

 

And this says that  b = 10^[log(2.5/.7)/190]  = about 1.0067

 

And we can solve this :

 

3 = .7(1.0067)x    where x is the damage we're looking for.......divide both sides by .7

 

3/.7  = 1.0067x        take the log of both sides

 

log(3/.7)  = log 1.0067x    and we can write

 

log (3/ .7)  = x log 1.0067      divide both sides by log1.0067

 

log (3 / .7)  / log( 1.0067) =  x  =  about  217.93  = 218  [rounded]

 

 

cool cool cool

CPhill Oct 1, 2015
 #2
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Thank you, :-)

 Oct 1, 2015

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