Hi. Here is the problem I have on my homework that I need help on.
In Super Smash Bros, Lucario is able to get stronger as he hits. His attack strength is 0.7 at 0 damage, but 2.5 strength at 190 damage. The highest he can go is a strength of 3, how much damage would be needed to get to that number (round up if the result becomes a decimal)?
It was hard to understand the problem myself, So I tried to make it a little more simple. Let me know if a part of the question does not make sense.
Also, Sorry if my english is bad, english isn't really my best area.
We can set this up as an exponential equation in this form :
y = abx ......where y is the attack strength, a is .7 , b is to be determined and x is the damage
And we're given :
2.5 = .7b190 divide both sides by .7
2.5/.7 = b190 take the log of both sides
log(2.5/.7) = log b190 and we can write this as
log(2.5/.7) = 190 logb divide both sides by 190
log(2.5/.7)/ 190 = log b
And this says that b = 10^[log(2.5/.7)/190] = about 1.0067
And we can solve this :
3 = .7(1.0067)x where x is the damage we're looking for.......divide both sides by .7
3/.7 = 1.0067x take the log of both sides
log(3/.7) = log 1.0067x and we can write
log (3/ .7) = x log 1.0067 divide both sides by log1.0067
log (3 / .7) / log( 1.0067) = x = about 217.93 = 218 [rounded]
We can set this up as an exponential equation in this form :
y = abx ......where y is the attack strength, a is .7 , b is to be determined and x is the damage
And we're given :
2.5 = .7b190 divide both sides by .7
2.5/.7 = b190 take the log of both sides
log(2.5/.7) = log b190 and we can write this as
log(2.5/.7) = 190 logb divide both sides by 190
log(2.5/.7)/ 190 = log b
And this says that b = 10^[log(2.5/.7)/190] = about 1.0067
And we can solve this :
3 = .7(1.0067)x where x is the damage we're looking for.......divide both sides by .7
3/.7 = 1.0067x take the log of both sides
log(3/.7) = log 1.0067x and we can write
log (3/ .7) = x log 1.0067 divide both sides by log1.0067
log (3 / .7) / log( 1.0067) = x = about 217.93 = 218 [rounded]