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A, B, C, and D are positive digits such that ABCD + BCD + CD + D = 2012. Find A + B + C + D

 Sep 28, 2020
 #1
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A = 1,  B = 4,  C = 6,  D = 8

 

1468 + 468 +68 + 8 =2012

 

1 + 4 + 6 + 8 = 19

 Sep 28, 2020

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