Given that measure of arc AF = 100º, arc = BD = 154º and arc AD = 40º.

What is the measure of ∠ AED?

http://s1266.photobucket.com/user/kittyparade/media/9009_zpsclzrcp2p.png.html?sort=3&o=0

A. 13º

B. 53º

C. 26º

D. 40º

We can use the Angle of Intersecting Chords Theorem

We first need to find the measure of minor arc FB....this is given by :

m arc FB = 360 - 100 - 154 - 40 = 66°

So...the measure of AED = (1/2) ( m arc FB + m arc AD) = (1/2) ( 66 + 40) = (1/2)(106) = 53°

Thank you so much.