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avatar+64 

Given that measure of arc AF = 100º, arc = BD = 154º and arc AD = 40º.

What is the measure of ∠ AED?

 

http://s1266.photobucket.com/user/kittyparade/media/9009_zpsclzrcp2p.png.html?sort=3&o=0

 

A. 13º

B. 53º

C. 26º

D. 40º

 Jun 6, 2018
 #1
avatar+101371 
+2

We can use the  Angle of  Intersecting Chords Theorem

 

We first need to find the measure  of  minor arc FB....this is given by :

 

m arc FB  = 360  - 100 - 154 - 40   = 66°

 

So...the measure of AED  = (1/2) ( m arc FB  + m arc AD)  =  (1/2) ( 66 + 40)  = (1/2)(106)  = 53°

 

 

cool cool cool

 Jun 6, 2018
 #2
avatar+64 
+2

Thank you so much.

THEMAN31  Jun 6, 2018

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