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I need help with this question very badly! Hope someone can help. 

 

 May 23, 2019
 #1
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a)  r  =      2

          __________       

            5 +  7cos θ

 

Standard Form  is

 

r  =     ep

      ___________

       1 + e cos θ

 

We  need   a "1" as a constant in the denominator to put this into SF.....divide every term by 5

 

r  =       2/5

       ____________

        1 + (7/5)cos θ

 

The eccentricity, e,  =   7/5

 

If

0 ≤ e < 1      we have an ellipse

e = 1     we have a parbola

1 < e  we have a hyperbola

 

So.....this is a hyperbola

 

(b)   If this is an ellipse....we must have that

 

0 ≤ e < 1

 

0 ≤ b / 5 < 1

 

0 ≤ b < 5

 

 

cool cool cool

 May 24, 2019

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