How many sides does a polygon have if the sum of its interior angles is 9000 degrees?
+9479 sum of interior angles of polygon = 180° * (the number of sides - 2)
We know the sum of the interior angles = 9000°
And let the number of sides = n
9000° = 180° * (n - 2)
Divide both sides of the equation by 180°
9000° / 180° = n - 2
50 = n - 2
Add 2 to both sides of the equation.
52 = n
n = 52
the number of sides = 52
+9479 sum of interior angles of polygon = 180° * (the number of sides - 2)
We know the sum of the interior angles = 9000°
And let the number of sides = n
9000° = 180° * (n - 2)
Divide both sides of the equation by 180°
9000° / 180° = n - 2
50 = n - 2
Add 2 to both sides of the equation.
52 = n
n = 52
the number of sides = 52
