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How many sides does a polygon have if the sum of its interior angles is 9000 degrees?

 Feb 6, 2020

Best Answer 

 #1
avatar+8873 
+2

sum of interior angles of polygon   =   180°  *  (the number of sides  -  2)

 

We know the sum of the interior angles  =  9000°

And let the number of sides  =  n

 

9000°   =   180°  *  (n - 2)

                                               Divide both sides of the equation by  180°

9000° / 180°   =   n - 2

 

50   =   n - 2

                         Add  2  to both sides of the equation.

52   =   n

 

n   =   52

 

the number of sides   =   52

 Feb 6, 2020
 #1
avatar+8873 
+2
Best Answer

sum of interior angles of polygon   =   180°  *  (the number of sides  -  2)

 

We know the sum of the interior angles  =  9000°

And let the number of sides  =  n

 

9000°   =   180°  *  (n - 2)

                                               Divide both sides of the equation by  180°

9000° / 180°   =   n - 2

 

50   =   n - 2

                         Add  2  to both sides of the equation.

52   =   n

 

n   =   52

 

the number of sides   =   52

hectictar Feb 6, 2020

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