Find the largest of three consecutive integers such that twice the greatest integer is the same as 12 less than 4 times the least integer.
( n + 2) * 2 =4n - 12, solve for n
n = 8 - the smallest number
The 3 numbers are: 8, 9, 10
Check: [2 * 10 =4 *8 - 12] =20 == 20