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Find the largest of three consecutive integers such that twice the greatest integer is the same as 12 less than 4 times the least integer.

 Dec 13, 2020
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( n + 2) * 2 =4n - 12, solve for n

 

n = 8 - the smallest number

 

The 3 numbers are: 8,  9,  10

 

Check: [2 * 10 =4 *8 - 12] =20 == 20

 Dec 13, 2020

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