+4 I've been trying to reacquaint myself with math and I have forgotten some pretty simple things...
Anyway, the word problem goes like this:
"Ms. Jones invested $18,000 in two accounts. One account pays 6% simple interst and the other pays 8%. Her total interest for the year was $1,290. How much did she have in each account?"
+23254 One way to work this problem is to use just one variable:
Let x represent the amount invested at 6%.
Since the total amount is $18,000.00, the other amount will be 18000 - x:
Let 18000 - x represent the amount invested at 8%.
The amount earned at 6% is 0.06·x (Rate x Amount)
The amount earned at 8% is 0.08·(18000 - x) (Rate x Amount)
The amount earned at 6% plus the amount earned at 8% equals the total amount earned ($1,290.00)
So, the equation is: 0.06·x + 0.08·(18000 - x) = 1290
Can you finish solving this equation?
+23254 One way to work this problem is to use just one variable:
Let x represent the amount invested at 6%.
Since the total amount is $18,000.00, the other amount will be 18000 - x:
Let 18000 - x represent the amount invested at 8%.
The amount earned at 6% is 0.06·x (Rate x Amount)
The amount earned at 8% is 0.08·(18000 - x) (Rate x Amount)
The amount earned at 6% plus the amount earned at 8% equals the total amount earned ($1,290.00)
So, the equation is: 0.06·x + 0.08·(18000 - x) = 1290
Can you finish solving this equation?
