A line with slope $-3$ passes through the points $(5,2)$ and $(9,y).$ Find $y.$
\(slope = \dfrac{y_2-y_1}{x_2-x_1} \\ -3 = \dfrac{y-2}{9-5} = \dfrac{y-2}{4}\\ y-2=-12 \\ y = -10\)
