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need help to find the value for this Q.Q

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cotθ and sinθ; secθ = - (9/2); sinθ >0

Guest Apr 17, 2017
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sec θ = -9/2

cos θ = -2/9

sin θ = sqrt(1 - cos2 θ) = $$\dfrac{\sqrt{77}}{9}$$

cot θ = cos θ / sin θ = $$\dfrac{\frac{-2}{9}}{\frac{\sqrt{77}}{9}}$$$$\dfrac{-2}{77}\sqrt{77}$$

MaxWong  Apr 17, 2017

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