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Need help, ty!

 Apr 23, 2018

y  = x^2 - 8x + 13


Let's put this in vertex form....complete the square on x


y  = x^2 - 8x + 16 + 13   - 16       factor the first three terms....simplify the rest


y  = (x -4)^2   - 3 


The vertex of this parabola  is    (4, -3)  .....it opens upward


Notice that the line that would be tangent to this parabola at the vertex would be the line  y  = -3 ⇒  "B"


So....this is the line that intersects the parabola in only one place


To  get a feel for this look at the following graph :  https://www.desmos.com/calculator/8gai6us8zr


Note that the other lines either intersect the graph twice....or not at all



cool cool cool

 Apr 23, 2018

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