In A, CD = 48 and the radius of the circle is 26. Find AG.
x(52 - x) = 242
x = 16, x = 36
242 = 576
576 / 16 = 36
AG = 26 - 16 = 10
\(AC=AD=26\)
\(CG=GD=24\)
\(AG=\sqrt{CA^2-CG^2}=\sqrt{676-576}=10\) (H)
+1641 
+150 
