+118658 1/8(-7x-14) = -7/2(m-3)
The denominators here are 8 and 2, the lowest common denominator is 8
with a question like this it is easiest to multiply both side by the lowest common denominator and that will get rid of all the fractions.
\(\frac{(-7x-14)}{8} = \frac{-7(m-3)}{2}\\ \frac{7(-x-2)}{8} = \frac{-7(m-3)}{2}\\ \frac{8}{1}\times \frac{-7(x+2)}{8} =\frac{8}{1}\times \frac{-7(m-3)}{2}\\ \frac{1}{1}\times \frac{-7(x+2)}{1} =\frac{4}{1}\times \frac{-7(m-3)}{1}\\ -7(x+2)=-28(m-3)\\ x+2=4(m-3)\\ x+2=4m-12\\ x=4m-14\\ \)
