A rectangle has an area of 315 cm² . If the length is increased by 2 cm and the width isdecreased by 2 cm, the area would decrease by 21 cm² Find the dimensions of the original rectangle (Round your answer to 3 significant figures where necessary.)
+36915 l * w = 315 l = 315/w
(l+2)(w-2) = 315 -21 = 294 sub red into this
(315/w + 2) (w-2) = 294
315 - 630/w + 2w -4 - 294 = 0
2w^2 + 17 w - 630 = 0 Quadratic Formula shows w = 14 cm then l = 315/14 = 22.5 cm (originally)
