Find three consecutive even integers such that the square of the third is 60 more that the square of the second
The 3 numbers are: 12, 14, 16
x-2, x, x+2
\((x+2)^2=x^2+60\\ x^2+4x+4=x^2+60\\ 4x+4=60\\ x+1=15\\ x=14\)
so like guest said, the numbers are 12,14, and 16
