\(5 = \frac{1}{3} (t-6)\)
I enter this equation in 2.0calc and I receive an answer of 21 but when I do it free hand I get a 11. How do I do this problem?
5 = (1/3)*(t-6)
divide both sides with 1/3 ( same as multiply both sides with 3 )
15 = t-6
add 6 to both sides
21=t
I see, thank you.