How many 5-digit numbers have at least one 2 or one 3 or one 4 among their digits?
+129847 Here's my attempt :
Total five -digit integers = (99999 - 10000 + 1) = 90000
The ones that DON'T contain any of these digits =
(6) (7) (7) (7) (7) = 14406
Total that DO contain at least one 2 or one 3 or one 4 among their digits =
90000 - 14406 =
75594
+515 I know that CPhill is making an answer rn but take a look at an old one to have some hints: https://web2.0calc.com/questions/help-please_56105
