1. remember cos^2 + sin^2 = 1
sin^2 = 1- cos^2
sin = sqrt (15/16) (we are only concerned about the POSITIVE root in the 1st quadrant)
tan = sin/cos sqrt(15/16) / 1/4 = 4 sqrt(15/16) = 3.873
2. sin (theta - pi/2) results in shifting the sin wave pi/2 to the right which is an inverted cos wave
so sin (theta-pi/2) is - cos(theta) = - .54
1. remember cos^2 + sin^2 = 1
sin^2 = 1- cos^2
sin = sqrt (15/16) (we are only concerned about the POSITIVE root in the 1st quadrant)
tan = sin/cos sqrt(15/16) / 1/4 = 4 sqrt(15/16) = 3.873
2. sin (theta - pi/2) results in shifting the sin wave pi/2 to the right which is an inverted cos wave
so sin (theta-pi/2) is - cos(theta) = - .54