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Given f(x) = (2x - 3)(x + 1), find the value of a such that f(3a-2) = 1.

 

I don't get this

 Nov 16, 2022
 #1
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I think that this would mean that when you plug 3a-2 into this equation you would get 1 so that would mean 1=(2x-3)(x+1) Expand to 2x2-x-3=1 set equal to 0 so 2x2-x-4=0 and then use the quadratic equation (1+-sqrt(1+32))/4 so 3a-2=(1+-sqrt(33))/4

 Nov 16, 2022
 #2
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Like this:

 

 Nov 16, 2022

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