Given f(x) = (2x - 3)(x + 1), find the value of a such that f(3a-2) = 1.
I don't get this
I think that this would mean that when you plug 3a-2 into this equation you would get 1 so that would mean 1=(2x-3)(x+1) Expand to 2x2-x-3=1 set equal to 0 so 2x2-x-4=0 and then use the quadratic equation (1+-sqrt(1+32))/4 so 3a-2=(1+-sqrt(33))/4
Like this:
