I think that this would mean that when you plug 3a-2 into this equation you would get 1 so that would mean 1=(2x-3)(x+1) Expand to 2x^{2}-x-3=1 set equal to 0 so 2x^{2}-x-4=0 and then use the quadratic equation (1+-sqrt(1+32))/4 so 3a-2=(1+-sqrt(33))/4