+0

# need help with math problem

0
48
3

Given the sequence defined by \$a_n = 48 - 3n\$, find all possible values of \$k\$ so that \[a_1 + a_2 + a_3 + \cdots + a_k = 330.\]

Sep 24, 2021

#1
0

Using the formula for an arithmetic series, k works out to 13.

Sep 24, 2021
#2
0

a=listfor(n, 1, 11, (48 - 3*n))=(45, 42, 39, 36, 33, 30, 27, 24, 21, 18, 15)==11 terms==330

Sep 24, 2021
#3
0

oh yeah forgot this was here i solved it already its 11 and 20 btw

Sep 24, 2021