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# Need help with math questions Please I'm confused

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Sharon will borrow \$3400 at 11% APR. She will pay it back over 18 months. What will her monthly payment be?  (Use The Table)

A) \$ 512.42
B) \$ 220.06
C) \$ 681.50 D)\$ 220.06 Jan 29, 2018

### 1+0 Answers

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You are asked to do the same thing in this question, but the Table you are given is for interest only.

The way they have calculated it, per \$100, is as follows: \$100 x 11% x 18 months/12 months=\$100 x 0.11 x 1.5 years =\$16.50 as you can see from the Table under 11% and across 18 months.

Then, they want you to calculate it for \$3,400. So, what you are supposed to do is the following:

\$3,400/\$100 x \$16.50/18 =\$31.17 - This is the monthly interest on \$3,400, which is calculated INCORRECTLY!!!.

Then, they want you to take \$3,400 / 18 months =\$188.89 of principal per month. Then you add this to the monthly interest of \$31.17. So, \$188.89+\$31.17 =\$220.06 - which is one of the "answers" given to you, which is INCORRECT. If you accept this payment, then the interest rate would have to be 19.92% compounded monthly.

The correct monthly payment can be calculated using the following formula:

PMT=PV. R.{[1 + R]^N/ [1 + R]^N - 1}

PMT=\$3,400 x 0.11/12{[1 + 0.11/12]^18 / [1 + 0.11/12]^18 - 1}

PMT=\$31.16667 x {[1.0091667]^18 / [1.0091667]^18 - 1}

PMT=\$31.16667 x {[1.1785069491] / [0.1785069491]}

PMT=\$31.16667 x           6.60202280493......

PMT=\$205.76 - This is the accurate monthly payment for the \$3,400 Loan @ 11% compounded monthly over a period of 18 months.

Jan 30, 2018