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If\[f(x) = \begin{cases} 2x-5 &\quad \text{if } x \ge 3, \\ -x + 5 &\quad \text{if } x < 3, \end{cases} \]then for how many values of $x$ is $f(f(x)) = 3$?

 Jan 4, 2022
 #1
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The only solultion is x = 1, so there is only one solution.

 Jan 4, 2022
 #2
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its seems that answer is incorrect but thanks for trying

Guest Jan 4, 2022
 #3
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The following graphs should help:

 Jan 4, 2022

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