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Jim can drive a golf ball over 200 yards 40% of the time. He regularly plays on a golf course where drives of that distance are needed on 12 holes. Determine the probability that exactly 7 of his drives will be over 220 yards.

 Feb 17, 2021
 #1
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I'm  thinking  that  the last  sentence   should  be  "over  200 yards"

P(any drive  is > 200 yds)  =.40

P (any drive is < 200 yds)   =1  -.40    =  .60

 

P( 7  of 12  are over 200 yds)    =   C(12,7) *  ( .40)^7  * (.60)^5    ≈   10%

 

 

cool cool cool

 Feb 17, 2021

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