My apologies, this is my last question for today. I tried looking inside of my old textbooks, but couldnt find a similar problem to work with. An explanation on how this is supposed to be done would be highly appreciated.
Add down the columns, you will get: 3x2 = 432
Divide by 3: x2 = 144
Find the square root: x = 12 or x = -12
If x = 12: substitute into the first equation: (12)2 + y2 = 289
144 + y2 = 289
y2 = 145
To solve this, find the square root; but the instructions say that you should find b, which is this number: 145.
The answer is (B) 145.
Add down the columns, you will get: 3x2 = 432
Divide by 3: x2 = 144
Find the square root: x = 12 or x = -12
If x = 12: substitute into the first equation: (12)2 + y2 = 289
144 + y2 = 289
y2 = 145
To solve this, find the square root; but the instructions say that you should find b, which is this number: 145.
The answer is (B) 145.