+0  
 
0
656
1
avatar+564 

 

My apologies, this is my last question for today. I tried looking inside of my old textbooks, but couldnt find a similar problem to work with. An explanation on how this is supposed to be done would be highly appreciated. 

 Dec 30, 2015

Best Answer 

 #1
avatar+23252 
+10

Add down the columns, you will get:  3x2  =  432

Divide by 3:                                          x2  =  144

Find the square root:                             x  =  12  or  x  =  -12

If  x = 12:  substitute into the first equation:  (12)2 + y2  =  289

                                                                       144 + y2  =  289

                                                                                 y2  =  145

To solve this, find the square root; but the instructions say that you should find b, which is this number:  145.

The answer is (B)  145.

 Dec 30, 2015
 #1
avatar+23252 
+10
Best Answer

Add down the columns, you will get:  3x2  =  432

Divide by 3:                                          x2  =  144

Find the square root:                             x  =  12  or  x  =  -12

If  x = 12:  substitute into the first equation:  (12)2 + y2  =  289

                                                                       144 + y2  =  289

                                                                                 y2  =  145

To solve this, find the square root; but the instructions say that you should find b, which is this number:  145.

The answer is (B)  145.

geno3141 Dec 30, 2015

4 Online Users

avatar