1. Let f(x)=4x-7, g(x)=(x+1)^2, and s(x)=f(x)+g(x). What is s(3)? 2. Let f(x)=2x^2+3x-9, g(x)=5x+11, and h(x)=-3x^2 +1. Find f(x)-g(x)+h(x)
f(x) = 4x - 7
g(x) = x^2 + 2x + 1
f(x) + g(x) = x^2 + 6x - 6
So s(3) = (3)^2 + 6(3) - 6 = 21
Second one ....add like you normally would after aligning the terms
2x ^2 + 3x - 9
+ 5x +11
-3x^2 + 1
_______________
-x^2 + 8x + 3
