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# Need help with this Expected Value prob

0
113
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+200

A fair 6-sided die is rolled. If I roll , n then I win n^2 dollars. What is the expected value of my win? Express your answer as a dollar value rounded to the nearest cent.

ColdplayMX  Aug 14, 2018
#1
0

The expected value of rolling one 6-sided die is: (1+2+3+4+5+6) / 6 =3.5

Your dollar winnings should be: 3.5^2 =\$12.25

Guest Aug 14, 2018
#3
+1198
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Solution:

$$\text {Expected Value } = (1/6)*(1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2) = \15.17$$

GA

GingerAle  Aug 15, 2018
#2
+200
+1

15.17.

ColdplayMX  Aug 15, 2018
#4
+1198
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Many math text books give answers to selected odd number questions.

Are you imitating your text book?

GA

GingerAle  Aug 15, 2018
#5
+93866
+1

Hi Ginger, it is nice to see you back again. :)

Melody  Aug 15, 2018