A fair 6-sided die is rolled. If I roll , n then I win n^2 dollars. What is the expected value of my win? Express your answer as a dollar value rounded to the nearest cent.
The expected value of rolling one 6-sided die is: (1+2+3+4+5+6) / 6 =3.5
Your dollar winnings should be: 3.5^2 =$12.25
Is this a brain-dead moment or your standard fare?
Solution:
\(\text {Expected Value } = (1/6)*(1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2) = \$15.17\)
GA
15.17.
Many math text books give answers to selected odd number questions.
Are you imitating your text book?
Hi Ginger, it is nice to see you back again. :)
+210 
