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A fair 6-sided die is rolled. If I roll , n then I win n^2 dollars. What is the expected value of my win? Express your answer as a dollar value rounded to the nearest cent.

ColdplayMX  Aug 14, 2018
 #1
avatar
0

The expected value of rolling one 6-sided die is: (1+2+3+4+5+6) / 6 =3.5

Your dollar winnings should be: 3.5^2 =$12.25

Guest Aug 14, 2018
 #3
avatar+1163 
+1

Is this a brain-dead moment or your standard fare?

 

Solution:

\(\text {Expected Value } = (1/6)*(1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2) = \$15.17\)

 

 

GA

GingerAle  Aug 15, 2018
 #2
avatar+199 
+1

15.17.

 

 

coolcoolcool

ColdplayMX  Aug 15, 2018
 #4
avatar+1163 
+1

 Many math text books give answers to selected odd number questions.

Are you imitating your text book? indecision

 

GA

GingerAle  Aug 15, 2018
 #5
avatar+93289 
+1

Hi Ginger, it is nice to see you back again. :)

Melody  Aug 15, 2018

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