We have a triangle $\triangle ABC$ and a point $K$ on $BC$ such that $AK$ is an altitude to $\triangle ABC$. If $AC = 8,$ $BK = 2$, and $CK = 3,$ then what is $AB$?
A
8
B 2 K 3 C
AKC , AKB are right triangles
AK = sqrt [8^2 - 3^2] = sqrt [ 55]
AB = sqrt [2^2 + 55] = sqrt [59]
+1790 
