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We have a triangle $\triangle ABC$ and a point $K$ on $BC$ such that $AK$ is an altitude to $\triangle ABC$. If $AC = 8,$ $BK = 2$, and $CK = 3,$ then what is $AB$?

 Jun 22, 2024
 #1
avatar+129725 
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              A

 

                    8

 

 

B       2   K      3          C

 

AKC , AKB  are right triangles

 

AK = sqrt [8^2 - 3^2]  = sqrt [ 55]

 

AB  = sqrt [2^2 + 55] =  sqrt [59]

 

 

cool cool cool

 Jun 22, 2024

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