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Let line 1 be the graph of 5x+8y=-9. Line 2 is perpendicular to line 1 and passes through the point (10,-10). If line 2 is the graph of the equation y=mx+b, then find m+b.

 Jul 8, 2021
 #1
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5x  +  8y  =  -9

Slope of  this line =  -5/8

Slope of a perp. line =  8/5

 

So  using (10 , -10)   we  have

 

y = (8/5)(x - 10  )   - 10

 

y = (8/5)x  - 16  -  10

 

y = (8/5)x - 26

 

m = 8/5     b  = -26

 

m +  b =    8/5  -  26  =  8/5  -  130/5  =  - 122 /  5

 

cool cool cool

 Jul 8, 2021

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