+0  
 
0
334
1
avatar

Show that if c does not equal 0 then the sum of the reciprocals of the roots of the quadratic equation ax^2+bx+c=0 is -b/c.

 May 24, 2021
 #1
avatar+178 
+1

Vietas, sum of reciprocals is x+y/xy and x+y is -b/a and xy is c/a so x+y/xy is -b/c

 May 24, 2021

4 Online Users