The quadratic equation $x^2-mx+24 = 10$ has roots $x_1$ and $x_2$. If $x_1$ and $x_2$ are integers, how many different values of $m$ are possible?
Simplify as
x^2 - mx + 14 = 0
Roots m
-1 -14 15
1 14 - 15
-2 -7 9
2 7 -9
Hi Chris,
So, I blundered into the right answer but for the wrong reason.
All the wrong reasons. Thanks for posting the correct answer.
Ron
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No prob.....I have those days when I should have just stayed in bed, too....
