The equation y = -16t^2 + 26t + 105 describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 feet above the ground. In how many seconds will the ball reach 110 feet? Express your answer as a decimal rounded to the nearest tenth.
+37157 y = 110
110 = -16t^2 + 26t + 105
0 = -16t^2 + 26t -5 Now use Quadratic Formula to calcualte 't' values,,,
the smaller t will be on the way up...the larger will be on the way down
a = -16 b = 26 c = -5
\(t = {-26 \pm \sqrt{26^2-4(-16)(-5)} \over 2(-16)}\)
