The equation y = -16t^2 + 26t + 105 describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 feet above the ground. In how many seconds will the ball reach 110 feet? Express your answer as a decimal rounded to the nearest tenth.

Guest Feb 11, 2022

#1**+1 **

y = 110

110 = -16t^2 + 26t + 105

0 = -16t^2 + 26t -5 Now use Quadratic Formula to calcualte 't' values,,,

the smaller t will be on the way up...the larger will be on the way down

a = -16 b = 26 c = -5

\(t = {-26 \pm \sqrt{26^2-4(-16)(-5)} \over 2(-16)}\)

ElectricPavlov Feb 11, 2022