Define a@b = ab - 2b and a#b = a + b - ab. What is (6@2)/(6#2)?
a@b = ab - 2b a#b = a + b - ab
So
(6 @ 2) / (6 # 2) =
(6*2 - 2*2) / ( 6 + 2 - 6*2) =
(8 ) / ( -4) =
-2