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The graph of a secant function shows no functional values on (−12, 12). The asymptotes of the function occur every π units.

Which function represents the secant function described?

f(x)=sec(x2)+12

f(x)=sec(x)+12

f(x)=12sec(x2)

f(x)=12sec(x)

 Mar 12, 2021
 #1
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f(x)  =  12sec (2x)

 

Here's  the graph  : https://www.desmos.com/calculator/7ivgku7b28

 

 

 

cool cool cool

 Mar 12, 2021

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