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\lim_{ a \rightarrow 16 } \frac { 16 - a } { 4 - \sqrt{a} }

need help!

 Feb 6, 2015

Best Answer 

 #4
avatar+118608 
+8

Hi Mathematicianoftheworld,

Like Chris said - what you have done is interlectual theft.

And, it is not a good look.

So

DON'T DO IT AGAIN. 

Now that I have taken care of that bit of business - Welcome to the web2 forum.

 Feb 7, 2015
 #1
avatar+128631 
+5

Notice that the top will factor as  [4 - √a] [4 + √a]

So we have

lim as  a → 16     [4 - √a] [4 + √a] / [4 - √a]  =

lim as  a → 16     [4 + √a]  =

4 + √16  =  4 + 4   = 8

 

 Feb 6, 2015
 #2
avatar+14 
0

Notice that the top will factor as  [4 - √a] [4 + √a]

So we have

lim as  a → 16     [4 - √a] [4 + √a] / [4 - √a]  =

lim as  a → 16     [4 + √a]  =

4 + √16  =  4 + 4   = 8

 
 
 #3
avatar+128631 
+5

C'mon, themathematicianoftheworld....if you're going to "steal" answers....at least try to make it LOOK like you have something original to add......

 

 Feb 6, 2015
 #4
avatar+118608 
+8
Best Answer

Hi Mathematicianoftheworld,

Like Chris said - what you have done is interlectual theft.

And, it is not a good look.

So

DON'T DO IT AGAIN. 

Now that I have taken care of that bit of business - Welcome to the web2 forum.

Melody Feb 7, 2015

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