The fifth term of an arithmetic sequence is 18, and the sum of the first 32 terms is \(1448\). Find the ninth term.
+36916 sum =1448= 32/ 2 ( a1 + a32)
a1 + a32 = 90.5
a1 = 18 - 4d a 32 = 18 + 27d
18-4d + 18 + 27d = 90.5
d = 2.3695652
18 + 4d = a9 = 27.478
