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# need help

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-4(-3x+5)-3x=3(x-4)-6

Guest Mar 6, 2017
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1. Multiply each term in the parenthesis by -4, 3

$$-4(-3x+5)-3x=3(x-4)-6$$

2. Calculate the product

Multiplying two negatives equals a positive: (-)*(-)=(+)

Use rules of multiplication to calculate the expression

$$-4\times (-3x)-4\times 5-3x=3x-12-6$$

3. Collect the like terms by subtracting their coefficients

Extract the negative sign from the expression

$$12x-20-3x=-3x=3x-12-6$$

4. Subtract the numbers

$$(12-3)x-20=3x-(12+6)$$

5. Move variable to the left by adding its opposite to both sides

Move constant to the right by adding its opposite to both sides

$$9x-20=3x-18$$

6. Eliminate the opposites

$$9x-3x-20+20=3x-3x-18+20$$

7. Collect the like terms by subtracting their coefficients

Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from the larger

$$9x-3x=-18+20$$

8. Subtract the numbers

$$(9-3)x=+(20-18)$$

9. Divide both sides of the equation by 6

$$6x=2$$

10. Any expression divided by itself equals 1

Write the division as a fraction

$$6x\div 6=2\div 6$$

11. Reduce the fraction with 2

$$x={2\over 6}$$

$$x={1\over 3}$$

Alternative form

$$x=\approx 0.333333$$

And there goes 30 minutes of my life...