+1886 1. Multiply each term in the parenthesis by -4, 3
\(-4(-3x+5)-3x=3(x-4)-6\)
2. Calculate the product
Multiplying two negatives equals a positive: (-)*(-)=(+)
Use rules of multiplication to calculate the expression
\(-4\times (-3x)-4\times 5-3x=3x-12-6\)
3. Collect the like terms by subtracting their coefficients
Extract the negative sign from the expression
\(12x-20-3x=-3x=3x-12-6\)
4. Subtract the numbers
Add the numbers
\((12-3)x-20=3x-(12+6)\)
5. Move variable to the left by adding its opposite to both sides
Move constant to the right by adding its opposite to both sides
\(9x-20=3x-18\)
6. Eliminate the opposites
\(9x-3x-20+20=3x-3x-18+20\)
7. Collect the like terms by subtracting their coefficients
Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from the larger
\(9x-3x=-18+20\)
8. Subtract the numbers
\((9-3)x=+(20-18)\)
9. Divide both sides of the equation by 6
\(6x=2\)
10. Any expression divided by itself equals 1
Write the division as a fraction
\(6x\div 6=2\div 6\)
11. Reduce the fraction with 2
\(x={2\over 6}\)
Answer
\(x={1\over 3}\)
Alternative form
\(x=\approx 0.333333\)
And there goes 30 minutes of my life...
