need help

1. Multiply each term in the parenthesis by -4, 3

$-4(-3x+5)-3x=3(x-4)-6$

 

2. Calculate the product

Multiplying two negatives equals a positive: (-)*(-)=(+)

Use rules of multiplication to calculate the expression

$-4\times (-3x)-4\times 5-3x=3x-12-6$

 

3. Collect the like terms by subtracting their coefficients

Extract the negative sign from the expression

$12x-20-3x=-3x=3x-12-6$

 

4. Subtract the numbers

Add the numbers

$(12-3)x-20=3x-(12+6)$

 

5. Move variable to the left by adding its opposite to both sides

Move constant to the right by adding its opposite to both sides

$9x-20=3x-18$

 

6. Eliminate the opposites

$9x-3x-20+20=3x-3x-18+20$

 

7. Collect the like terms by subtracting their coefficients

Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from the larger

$9x-3x=-18+20$

 

8. Subtract the numbers

$(9-3)x=+(20-18)$

 

9. Divide both sides of the equation by 6

$6x=2$

 

10. Any expression divided by itself equals 1

Write the division as a fraction

$6x\div 6=2\div 6$

 

11. Reduce the fraction with 2

$x={2\over 6}$

 

Answer

$x={1\over 3}$

 

Alternative form

$x=\approx 0.333333$

 

 

 

And there goes 30 minutes of my life...