+0  
 
0
63
2
avatar

The difference of two numbers is 36. The large number is 4 more than twice the smaller number. What are the numbers?

 Jan 14, 2020
 #1
avatar
+1

IF I understand the question correctly you can use this formula.
Since the difference between them is 36, we let X be the large number and y the small. Therefore X-Y=36. Since X is 4+2*y we can substitute X in the equation so X-Y=36 Becomes =4+2*Y-Y=36. Solve by 2*y-y=36-4=>y=32. Since x is 4+2*y we have... X=32*2+4=> X=68

 Jan 14, 2020
 #2
avatar+22096 
+2

x-y = 36

 

x = 2y +4

 

 

sub into the first equation

 

2y+4 - y = 36

y = 32

then    x = 2y+4 = 68  

 Jan 14, 2020
edited by ElectricPavlov  Jan 14, 2020
edited by ElectricPavlov  Jan 14, 2020

7 Online Users